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Yoshinobu Yamamoto loses perfect game on Mookie Betts error

sportsJun 13, 202631575

Yoshinobu Yamamoto lost a perfect game when Mookie Betts misplayed a two out grounder in the eighth inning at Guaranteed Rate Field against the Chicago White Sox. Yamamoto had retired every batter through seven and finished 8.1 innings with one hit, one earned run, zero walks and seven strikeouts. Tristan Peters ended the no-hit bid with a solo homer in the ninth, and Yamamoto's run of 45 consecutive batters retired fell one short of Yusmeiro Petit's modern-era record of 46. The outing underscores Yamamoto's dominance this season and how a single defensive mistake can erase a historic milestone while keeping him firmly in Cy Young conversation.

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